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1 point by evanrmurphy 2516 days ago | link | parent

> Well, there are definitely fewer conses in ((a b) 1 2) than in ((a 1) (b 2)), but ((a . 1) (b . 2)) has them both beat. (Maybe I'm missing something.)

I resorted to cons counting to confirm it for my own simple mind and... you're correct! ^_^

  ; bucket (5 conses)
  ((a . (b . nil))  . (1 . (2 . nil)) )

  ; "frugal" alist (4 conses)
  ((a . b) . ((b . 2) . nil))
Note, however, that it's a constant difference of 1 cons. The difference doesn't grow with the size of the data, so it's rather insignificant.

Sorry I don't have time to respond to the rest of your comment right now.