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2 points by Jesin 5871 days ago | link | parent

I wonder how we would deal with this:

  [(foo _ _) baz _]
Does that mean

  (fn (x) ((foo x x) baz x))
or does it mean

  (fn (x) ((fn (y) (fn (z) (foo y z))) baz x))


1 point by cchooper 5871 days ago | link

It would mean the former. I think that's the only sensible way to do it.

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