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1 point by almkglor 5827 days ago | link | parent

This is because the expression:

  (and:or nil t)
expands to:

  (and (or nil t))
But the expression:

  (idfn and:or)
Expands to:

  (idfn (compose and or))
If you read my comment well, you'll see that I specifically mentioned that:

> You see, foo:bar in function position is handled specially:



2 points by absz 5827 days ago | link

Actually, I believe what's happening is that

  (and:or nil t)
becomes

  ((compose and or) nil t)
, which is then expanded to

  (and (or nil t))
by ac.scm. Observe:

  arc> ((compose and or) nil t)
  t

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